中点 (-7/3 , 3/4),(5/3 ,-9/4)

解答

中点

(- \frac{7}{3}, \frac{3}{4}), (\frac{5}{3}, - \frac{9}{4})

(- \frac{1}{3}, - \frac{3}{4})

求解步骤

(x_{1}, y_{1}), (x_{2}, y_{2})

的中点:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- \frac{7}{3}, \frac{3}{4}), (x_{2}, y_{2}) = (\frac{5}{3}, - \frac{9}{4})

= (\frac{\frac{5}{3} - \frac{7}{3}}{2}, \frac{- \frac{9}{4} + \frac{3}{4}}{2})

整理后得

= (- \frac{1}{3}, - \frac{3}{4})

r = 4

2 e^{x}

(- 4, - \frac{π}{3})

y = \frac{1}{x ^{2}}

12 x + 6 y = 18