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midpoint
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polar (1,1)cartesian to polar y=-xperpendicular y=3x-2,(3,7)perpendicular derivative of f(x)=sec^2(x)derivative of derivative of y=3x^3+1/4 x^2derivative of
Frequently Asked Questions (FAQ)
What is the midpoint (17,-11),(-14,-16) ?
The midpoint (17,-11),(-14,-16) is (3/2 ,-27/2)