What is the tangent of sin(x+y)=2x-2y,(pi,pi) ?

The tangent of sin(x+y)=2x-2y,(pi,pi) is y= 1/3 x+pi-pi/3

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tangent of sin(x+y)=2x-2y,(pi,pi)

tangent of

sin (x + y) = 2 x - 2 y, (π, π)

y = \frac{1}{3} x + π - \frac{π}{3}

Solution steps

Find the slope of

sin (x + y) = 2 x - 2 y : \frac{d y}{d x} = \frac{2 - cos ( x + y )}{cos ( x + y ) + 2}

Compute the slope of

sin (x + y) = 2 x - 2 y

(π, π) : m = \frac{1}{3}

Find the line with slope m=

\frac{1}{3}

and passing through

(π, π) : y = \frac{1}{3} x + π - \frac{π}{3}

y = \frac{1}{3} x + π - \frac{π}{3}

2 cos (x)

(1, 6), (5, 8)

e^{- x}

y = csc (x) cot (x)

y = x^{2}

What is the tangent of sin(x+y)=2x-2y,(pi,pi) ?
The tangent of sin(x+y)=2x-2y,(pi,pi) is y= 1/3 x+pi-pi/3