What is the tangent of f(x)=x^2+6x+1,\at x=-2 ?

The tangent of f(x)=x^2+6x+1,\at x=-2 is y=2x-3

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tangent of f(x)=x^2+6x+1,\at x=-2

tangent of

f (x) = x^{2} + 6 x + 1, at x = - 2

y = 2 x - 3

Solution steps

Find the tangent point:

(- 2, - 7)

Find the slope of

f (x) = x^{2} + 6 x + 1 : \frac{df ( x )}{d x} = 2 x + 6

Compute the slope of

f (x) = x^{2} + 6 x + 1

x = - 2 : m = 2

Find the line with slope m=

2

and passing through

(- 2, - 7) : y = 2 x - 3

y = 2 x - 3

(- 4, 3)

y = e^{e^{x}}

x x + 1

(1, - 6), (- 3, 4)

x^{3} + y^{3} = 6 x y

What is the tangent of f(x)=x^2+6x+1,\at x=-2 ?
The tangent of f(x)=x^2+6x+1,\at x=-2 is y=2x-3