What is derivative of f(x)=t^2ln(e^{2t}+1) ?

The answer to derivative of f(x)=t^2ln(e^{2t}+1) is (dt)/(dx)=0

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derivative of f(x)=t^2ln(e^{2t}+1)

derivative of

f (x) = t^{2} ln (e^{2 t} + 1)

\frac{d t}{d x} = 0

Solution steps

f (x) = t^{2} ln (e^{2 t} + 1)

Treat

t

t (x)

Differentiate both sides:

0 = 2 ln (e^{2 t} + 1) t \frac{d t}{d x} + \frac{2 e ^{2 t} \frac{d t}{d x} t ^{2}}{e ^{2 t} + 1}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

(2, - 2)

2 x + 4 y = 7

f (x) = x^{2} ln (x)

f (x) = \frac{1}{x - 1}

(1, 9), (6, 3)

What is derivative of f(x)=t^2ln(e^{2t}+1) ?
The answer to derivative of f(x)=t^2ln(e^{2t}+1) is (dt)/(dx)=0