What is the general solution for 2cos(2x)=0 ?

The general solution for 2cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin

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2cos(2x)=0

2 cos (2 x) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

2 cos (2 x) = 0

Divide both sides by

2

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

sin^{2} (x) - sin (x) = 0

sec (x) = - 1

sin^{2} (θ) - cos^{2} (θ) = 1 + cos (θ)

cos (x) sin (x) - 2 cos (x) = 0

csc (x) = - 2

What is the general solution for 2cos(2x)=0 ?
The general solution for 2cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin