What is the general solution for 2sin^2(x)-sin(x)=0 ?

The general solution for 2sin^2(x)-sin(x)=0 is x= pi/6+2pin,x=(5pi)/6+2pin,x=2pin,x=pi+2pin

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2sin^2(x)-sin(x)=0

2 sin^{2} (x) - sin (x) = 0

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = 2 πn, x = π + 2 πn

Solution steps

2 sin^{2} (x) - sin (x) = 0

Solve by substitution

sin (x) = \frac{1}{2}, sin (x) = 0

sin (x) = \frac{1}{2} : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = 2 πn, x = π + 2 πn

3 tan (x) + 1 = 0

sec (2 x) = 2

cos^{2} (x) = 1 - sin (x)

cos (x) = - \frac{1}{2}

cos (x) = - 0.5

What is the general solution for 2sin^2(x)-sin(x)=0 ?
The general solution for 2sin^2(x)-sin(x)=0 is x= pi/6+2pin,x=(5pi)/6+2pin,x=2pin,x=pi+2pin