What is the general solution for 2cos^2(x)+3sin(x)=0 ?

The general solution for 2cos^2(x)+3sin(x)=0 is x=(7pi)/6+2pin,x=(11pi)/6+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos^2(x)+3sin(x)=0

2 cos^{2} (x) + 3 sin (x) = 0

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solution steps

2 cos^{2} (x) + 3 sin (x) = 0

Rewrite using trig identities

(1 - sin^{2} (x)) \cdot 2 + 3 sin (x) = 0

Solve by substitution

sin (x) = - \frac{1}{2}, sin (x) = 2

sin (x) = - \frac{1}{2} : x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

sin (x) = 2 :

No Solution

Combine all the solutions

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

tan (3 x) - 1 = 0

2 sin (2 x) - 1 = 0

sin (2 x) = \frac{2}{2}

csc (x) + 1 = 0

tan^{2} (θ) = 1

What is the general solution for 2cos^2(x)+3sin(x)=0 ?
The general solution for 2cos^2(x)+3sin(x)=0 is x=(7pi)/6+2pin,x=(11pi)/6+2pin