What is the general solution for sin^2(x)-2sin(x)-3=0 ?

The general solution for sin^2(x)-2sin(x)-3=0 is x=(3pi)/2+2pin

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sin^2(x)-2sin(x)-3=0

sin^{2} (x) - 2 sin (x) - 3 = 0

x = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (x) - 2 sin (x) - 3 = 0

Solve by substitution

sin (x) = 3, sin (x) = - 1

sin (x) = 3 :

No Solution

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

2 cos (x) + sin (2 x) = 0, 0 \leq x \leq 2 π

tan^{2} (x) sin (x) = sin (x)

2 sin (2 x) - 3 = 0

2 sin (x) cos (x) = 0

tan^{5} (x) - 9 tan (x) = 0

What is the general solution for sin^2(x)-2sin(x)-3=0 ?
The general solution for sin^2(x)-2sin(x)-3=0 is x=(3pi)/2+2pin