What is the general solution for 2sin(2x)-sqrt(3)=0 ?

The general solution for 2sin(2x)-sqrt(3)=0 is x= pi/6+pin,x= pi/3+pin

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2sin(2x)-sqrt(3)=0

2 sin (2 x) - 3 = 0

x = \frac{π}{6} + πn, x = \frac{π}{3} + πn

Solution steps

2 sin (2 x) - 3 = 0

Move

3

to the right side

2 sin (2 x) = 3

Divide both sides by

2

sin (2 x) = \frac{3}{2}

General solutions for

sin (2 x) = \frac{3}{2}

2 x = \frac{π}{3} + 2 πn, 2 x = \frac{2 π}{3} + 2 πn

Solve

2 x = \frac{π}{3} + 2 πn : x = \frac{π}{6} + πn

Solve

2 x = \frac{2 π}{3} + 2 πn : x = \frac{π}{3} + πn

x = \frac{π}{6} + πn, x = \frac{π}{3} + πn

2 sin (x) cos (x) = 0

tan^{5} (x) - 9 tan (x) = 0

1 - cos (θ) = \frac{1}{2}

(tan (θ) - 1) (cos (θ) + 1) = 0

sin^{2} (θ) = cos^{2} (θ)

What is the general solution for 2sin(2x)-sqrt(3)=0 ?
The general solution for 2sin(2x)-sqrt(3)=0 is x= pi/6+pin,x= pi/3+pin