What is the general solution for (tan(θ)-1)(cos(θ)+1)=0 ?

The general solution for (tan(θ)-1)(cos(θ)+1)=0 is θ= pi/4+pin,θ=pi+2pin

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(tan(θ)-1)(cos(θ)+1)=0

(tan (θ) - 1) (cos (θ) + 1) = 0

θ = \frac{π}{4} + πn, θ = π + 2 πn

Solution steps

(tan (θ) - 1) (cos (θ) + 1) = 0

Solving each part separately

tan (θ) - 1 = 0 or cos (θ) + 1 = 0

tan (θ) - 1 = 0 : θ = \frac{π}{4} + πn

cos (θ) + 1 = 0 : θ = π + 2 πn

Combine all the solutions

θ = \frac{π}{4} + πn, θ = π + 2 πn

sin^{2} (θ) = cos^{2} (θ)

x, sin (x) = 0

cos (θ) = \frac{2}{5}

2 cos^{2} (x) = cos (x)

sin (y) = 0

What is the general solution for (tan(θ)-1)(cos(θ)+1)=0 ?
The general solution for (tan(θ)-1)(cos(θ)+1)=0 is θ= pi/4+pin,θ=pi+2pin