What is the general solution for cos(5x)=1,0<= x<= 2pi ?

The general solution for cos(5x)=1,0<= x<= 2pi is x=0,x=(2pi)/5 ,x=(4pi)/5 ,x=(6pi)/5 ,x=(8pi)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(5x)=1,0<= x<= 2pi

cos (5 x) = 1, 0 \leq x \leq 2 π

x = 0, x = \frac{2 π}{5}, x = \frac{4 π}{5}, x = \frac{6 π}{5}, x = \frac{8 π}{5}

Solution steps

cos (5 x) = 1, 0 \leq x \leq 2 π

General solutions for

cos (5 x) = 1

5 x = 0 + 2 πn

Solve

5 x = 0 + 2 πn : x = \frac{2 πn}{5}

x = \frac{2 πn}{5}

Solutions for the range

0 \leq x \leq 2 π

x = 0, x = \frac{2 π}{5}, x = \frac{4 π}{5}, x = \frac{6 π}{5}, x = \frac{8 π}{5}

sec (2 θ) = 2, 0 < θ < \frac{π}{2}

2 cos (2 θ) + 1 = 0

sec (\frac{5 θ}{4}) = 2

sin^{2} (x) = 1 - cos (x)

3 sec (x) - 4 cos (x) = 0

What is the general solution for cos(5x)=1,0<= x<= 2pi ?
The general solution for cos(5x)=1,0<= x<= 2pi is x=0,x=(2pi)/5 ,x=(4pi)/5 ,x=(6pi)/5 ,x=(8pi)/5