What is the general solution for cos^2(x)=sin^2(x) ?

The general solution for cos^2(x)=sin^2(x) is x= pi/4+pin,x=(3pi)/4+pin

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cos^2(x)=sin^2(x)

cos^{2} (x) = sin^{2} (x)

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

cos^{2} (x) = sin^{2} (x)

Subtract

sin^{2} (x)

from both sides

cos^{2} (x) - sin^{2} (x) = 0

Rewrite using trig identities

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

sin (x + \frac{π}{4}) + sin (x - \frac{π}{4}) = - 1

cos (\frac{x}{4}) = 0

cos (θ) = 0.92

2 sin (2 x) = 1

2 cos (x) = 2

What is the general solution for cos^2(x)=sin^2(x) ?
The general solution for cos^2(x)=sin^2(x) is x= pi/4+pin,x=(3pi)/4+pin