What is the general solution for 3sin(2t)+4=1 ?

The general solution for 3sin(2t)+4=1 is t=(3pi)/4+pin

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3sin(2t)+4=1

3 sin (2 t) + 4 = 1

t = \frac{3 π}{4} + πn

Solution steps

3 sin (2 t) + 4 = 1

Move

4

to the right side

3 sin (2 t) = - 3

Divide both sides by

3

sin (2 t) = - 1

General solutions for

sin (2 t) = - 1

2 t = \frac{3 π}{2} + 2 πn

Solve

2 t = \frac{3 π}{2} + 2 πn : t = \frac{3 π}{4} + πn

t = \frac{3 π}{4} + πn

x, cos (x) = 0

cos (x + \frac{π}{6}) - cos (x - \frac{π}{6}) = 1

tan (2 θ) + 2 sin (θ) = 0

2 cos^{2} (x) + 7 sin (x) = 5

tan^{2} (x) + sec (x) = 1

What is the general solution for 3sin(2t)+4=1 ?
The general solution for 3sin(2t)+4=1 is t=(3pi)/4+pin