What is the general solution for sin(2x)+1=0 ?

The general solution for sin(2x)+1=0 is x=(3pi)/4+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(2x)+1=0

sin (2 x) + 1 = 0

x = \frac{3 π}{4} + πn

Solution steps

sin (2 x) + 1 = 0

Move

1

to the right side

sin (2 x) = - 1

General solutions for

sin (2 x) = - 1

2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

cos (2 x) cos (x) + sin (2 x) sin (x) = 1

cos (2 θ) + 10 sin^{2} (θ) = 7

4 cos (2 t) + 1 = 3

cos (2 x) - cos (x) = - 1

cos (x + \frac{π}{4}) - cos (x - \frac{π}{4}) = 1

What is the general solution for sin(2x)+1=0 ?
The general solution for sin(2x)+1=0 is x=(3pi)/4+pin