What is the general solution for cos(4x)=-(sqrt(2))/2 ?

The general solution for cos(4x)=-(sqrt(2))/2 is x=(3pi}{16}+(pin)/2 ,x=(5pi)/(16)+\frac{pin)/2

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cos(4x)=-(sqrt(2))/2

cos (4 x) = - \frac{2}{2}

x = \frac{3 π}{16} + \frac{πn}{2}, x = \frac{5 π}{16} + \frac{πn}{2}

Solution steps

cos (4 x) = - \frac{2}{2}

General solutions for

cos (4 x) = - \frac{2}{2}

4 x = \frac{3 π}{4} + 2 πn, 4 x = \frac{5 π}{4} + 2 πn

Solve

4 x = \frac{3 π}{4} + 2 πn : x = \frac{3 π}{16} + \frac{πn}{2}

Solve

4 x = \frac{5 π}{4} + 2 πn : x = \frac{5 π}{16} + \frac{πn}{2}

x = \frac{3 π}{16} + \frac{πn}{2}, x = \frac{5 π}{16} + \frac{πn}{2}

tan (x) = 2 sin (x)

cos (2 x) + 3 cos (x) + 2 = 0

tan (θ) + 1 = sec (θ)

2 sin (θ) = 2

5 cos (x) - 3 = 3 cos (x)

What is the general solution for cos(4x)=-(sqrt(2))/2 ?
The general solution for cos(4x)=-(sqrt(2))/2 is x=(3pi}{16}+(pin)/2 ,x=(5pi)/(16)+\frac{pin)/2