What is the general solution for sin^2(θ)+sin(θ)=0 ?

The general solution for sin^2(θ)+sin(θ)=0 is θ=2pin,θ=pi+2pin,θ=(3pi)/2+2pin

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sin^2(θ)+sin(θ)=0

sin^{2} (θ) + sin (θ) = 0

θ = 2 πn, θ = π + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (θ) + sin (θ) = 0

Solve by substitution

sin (θ) = 0, sin (θ) = - 1

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

sin (θ) = - 1 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = 2 πn, θ = π + 2 πn, θ = \frac{3 π}{2} + 2 πn

cos^{2} (θ) - sin^{2} (θ) = sin (θ) + 1

tan (x) = - \frac{1}{2}

sin (θ) + cos (θ) = 1

cos (x^{2}) = 0

sec^{2} (x) = 2 sec (x)

What is the general solution for sin^2(θ)+sin(θ)=0 ?
The general solution for sin^2(θ)+sin(θ)=0 is θ=2pin,θ=pi+2pin,θ=(3pi)/2+2pin