What is the general solution for 4cos(x)=1 ?

The general solution for 4cos(x)=1 is x=1.31811…+2pin,x=2pi-1.31811…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4cos(x)=1

4 cos (x) = 1

x = 1.31811 \dots + 2 πn, x = 2 π - 1.31811 \dots + 2 πn

Solution steps

4 cos (x) = 1

Divide both sides by

4

cos (x) = \frac{1}{4}

Apply trig inverse properties

x = arccos (\frac{1}{4}) + 2 πn, x = 2 π - arccos (\frac{1}{4}) + 2 πn

Show solutions in decimal form

x = 1.31811 \dots + 2 πn, x = 2 π - 1.31811 \dots + 2 πn

sin^{4} (x) = \frac{( cos ^{2} ( x ) )}{2}

cos^{2} (x) - cos (x) - 1 = 0

9 sin (18 x) + 11 = 2

3 sin (2 x) = 0

8 cos^{2} (θ) = 2

What is the general solution for 4cos(x)=1 ?
The general solution for 4cos(x)=1 is x=1.31811…+2pin,x=2pi-1.31811…+2pin