What is the general solution for 9sin(18x)+11=2 ?

The general solution for 9sin(18x)+11=2 is x= pi/(12)+(pin)/9

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9sin(18x)+11=2

9 sin (18 x) + 11 = 2

x = \frac{π}{12} + \frac{πn}{9}

Solution steps

9 sin (18 x) + 11 = 2

Move

11

to the right side

9 sin (18 x) = - 9

Divide both sides by

9

sin (18 x) = - 1

General solutions for

sin (18 x) = - 1

18 x = \frac{3 π}{2} + 2 πn

Solve

18 x = \frac{3 π}{2} + 2 πn : x = \frac{π}{12} + \frac{πn}{9}

x = \frac{π}{12} + \frac{πn}{9}

3 sin (2 x) = 0

8 cos^{2} (θ) = 2

tan (2 θ) - 2 sin (θ) = 0

sin (x) cos (x) = 3 cos (x)

sin (π x) = 0

What is the general solution for 9sin(18x)+11=2 ?
The general solution for 9sin(18x)+11=2 is x= pi/(12)+(pin)/9