What is the general solution for tan^2(x)-1=0,0<= x<= 2pi ?

The general solution for tan^2(x)-1=0,0<= x<= 2pi is x= pi/4 ,x=(5pi)/4 ,x=(3pi)/4 ,x=(7pi)/4

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tan^2(x)-1=0,0<= x<= 2pi

tan^{2} (x) - 1 = 0, 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}, x = \frac{3 π}{4}, x = \frac{7 π}{4}

Solution steps

tan^{2} (x) - 1 = 0, 0 \leq x \leq 2 π

Solve by substitution

tan (x) = 1, tan (x) = - 1

tan (x) = 1, 0 \leq x \leq 2 π : x = \frac{π}{4}, x = \frac{5 π}{4}

tan (x) = - 1, 0 \leq x \leq 2 π : x = \frac{3 π}{4}, x = \frac{7 π}{4}

Combine all the solutions

x = \frac{π}{4}, x = \frac{5 π}{4}, x = \frac{3 π}{4}, x = \frac{7 π}{4}

sin^{2} (θ) = \frac{1}{4}

(tan (θ) + 1) (sec (θ) + 1) = 0

2 sin (θ) - tan^{2} (θ) = 0

sin (θ) - 3 cos (θ) = 1

cos (a) = \frac{1}{2}

What is the general solution for tan^2(x)-1=0,0<= x<= 2pi ?
The general solution for tan^2(x)-1=0,0<= x<= 2pi is x= pi/4 ,x=(5pi)/4 ,x=(3pi)/4 ,x=(7pi)/4