What is the general solution for sin(θ/2)=-(sqrt(3))/2 ?

The general solution for sin(θ/2)=-(sqrt(3))/2 is θ=(8pi)/3+4pin,θ=(10pi)/3+4pin

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sin(θ/2)=-(sqrt(3))/2

sin (\frac{θ}{2}) = - \frac{3}{2}

θ = \frac{8 π}{3} + 4 πn, θ = \frac{10 π}{3} + 4 πn

Solution steps

sin (\frac{θ}{2}) = - \frac{3}{2}

General solutions for

sin (\frac{θ}{2}) = - \frac{3}{2}

\frac{θ}{2} = \frac{4 π}{3} + 2 πn, \frac{θ}{2} = \frac{5 π}{3} + 2 πn

Solve

\frac{θ}{2} = \frac{4 π}{3} + 2 πn : θ = \frac{8 π}{3} + 4 πn

Solve

\frac{θ}{2} = \frac{5 π}{3} + 2 πn : θ = \frac{10 π}{3} + 4 πn

θ = \frac{8 π}{3} + 4 πn, θ = \frac{10 π}{3} + 4 πn

cos (θ) = 0.98

sec^{2} (x) = 3 tan^{2} (x) - 1

csc (x) + cot (x) = \frac{3}{3}

sin (θ) + 1 = cos (θ)

2 sin^{2} (θ) - sin (θ) = 0

What is the general solution for sin(θ/2)=-(sqrt(3))/2 ?
The general solution for sin(θ/2)=-(sqrt(3))/2 is θ=(8pi)/3+4pin,θ=(10pi)/3+4pin