What is the general solution for 4cos^2(x)-1=0,0<x<2pi ?

The general solution for 4cos^2(x)-1=0,0<x<2pi is x= pi/3 ,x=(5pi)/3 ,x=(2pi)/3 ,x=(4pi)/3

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4cos^2(x)-1=0,0<x<2pi

4 cos^{2} (x) - 1 = 0, 0 < x < 2 π

x = \frac{π}{3}, x = \frac{5 π}{3}, x = \frac{2 π}{3}, x = \frac{4 π}{3}

Solution steps

4 cos^{2} (x) - 1 = 0, 0 < x < 2 π

Solve by substitution

cos (x) = \frac{1}{2}, cos (x) = - \frac{1}{2}

cos (x) = \frac{1}{2}, 0 < x < 2 π : x = \frac{π}{3}, x = \frac{5 π}{3}

cos (x) = - \frac{1}{2}, 0 < x < 2 π : x = \frac{2 π}{3}, x = \frac{4 π}{3}

Combine all the solutions

x = \frac{π}{3}, x = \frac{5 π}{3}, x = \frac{2 π}{3}, x = \frac{4 π}{3}

cos (\frac{2 x - π}{6}) = \frac{( 3 )}{2}, 0 < x < 2 π

4 sin (\frac{t}{2}) - 1 = 1

2 cos^{2} (x) = sin (2 x)

tan (θ) + cot (θ) = 4 sin (2 θ)

2 cos^{2} (θ) - 7 cos (θ) + 3 = 0

What is the general solution for 4cos^2(x)-1=0,0<x<2pi ?
The general solution for 4cos^2(x)-1=0,0<x<2pi is x= pi/3 ,x=(5pi)/3 ,x=(2pi)/3 ,x=(4pi)/3