What is the general solution for sec(5x)-2=0 ?

The general solution for sec(5x)-2=0 is x= pi/(15)+(2pin)/5 ,x= pi/3+(2pin)/5

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sec(5x)-2=0

sec (5 x) - 2 = 0

x = \frac{π}{15} + \frac{2 πn}{5}, x = \frac{π}{3} + \frac{2 πn}{5}

Solution steps

sec (5 x) - 2 = 0

Move

2

to the right side

sec (5 x) = 2

General solutions for

sec (5 x) = 2

5 x = \frac{π}{3} + 2 πn, 5 x = \frac{5 π}{3} + 2 πn

Solve

5 x = \frac{π}{3} + 2 πn : x = \frac{π}{15} + \frac{2 πn}{5}

Solve

5 x = \frac{5 π}{3} + 2 πn : x = \frac{π}{3} + \frac{2 πn}{5}

x = \frac{π}{15} + \frac{2 πn}{5}, x = \frac{π}{3} + \frac{2 πn}{5}

sin (z) = 0

4 sec (x) + 4 tan (x) = 4

8 sin (2 x) sin (x) = 8 cos (x)

cos (x) = - \frac{3}{4}

2 cos^{2} (x) + cos (x) - 1 = 0, 0 \leq x \leq 2 π

What is the general solution for sec(5x)-2=0 ?
The general solution for sec(5x)-2=0 is x= pi/(15)+(2pin)/5 ,x= pi/3+(2pin)/5