What is the general solution for sin(2x)=-cos(2x) ?

The general solution for sin(2x)=-cos(2x) is x=(3pi)/8+(pin)/2

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sin(2x)=-cos(2x)

sin (2 x) = - cos (2 x)

x = \frac{3 π}{8} + \frac{πn}{2}

Solution steps

sin (2 x) = - cos (2 x)

Rewrite using trig identities

tan (2 x) = - 1

General solutions for

tan (2 x) = - 1

2 x = \frac{3 π}{4} + πn

Solve

2 x = \frac{3 π}{4} + πn : x = \frac{3 π}{8} + \frac{πn}{2}

x = \frac{3 π}{8} + \frac{πn}{2}

3 sin (4 x) + 5 = 6

4 sin (x) + 3 = 0

tan (2 θ) = 3

cos (x) = 0.2

sin (2 x) - \frac{3}{2} = 0

What is the general solution for sin(2x)=-cos(2x) ?
The general solution for sin(2x)=-cos(2x) is x=(3pi)/8+(pin)/2