What is the general solution for tan^2(θ)-2tan(θ)=0 ?

The general solution for tan^2(θ)-2tan(θ)=0 is θ=1.10714…+pin,θ=pin

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tan^2(θ)-2tan(θ)=0

tan^{2} (θ) - 2 tan (θ) = 0

θ = 1.10714 \dots + πn, θ = πn

Solution steps

tan^{2} (θ) - 2 tan (θ) = 0

Solve by substitution

tan (θ) = 2, tan (θ) = 0

tan (θ) = 2 : θ = arctan (2) + πn

tan (θ) = 0 : θ = πn

Combine all the solutions

θ = arctan (2) + πn, θ = πn

Show solutions in decimal form

θ = 1.10714 \dots + πn, θ = πn

sin (6 x) cos (x) = - cos (6 x) sin (x)

x, cos (x y) = 1 + sin (y)

4 sin (x) - 1 = 2 sin (x) + 1

sin (3 x) = \frac{3}{4}

sin (x + \frac{π}{3}) + cos (x + \frac{π}{6}) = \frac{3}{3}

What is the general solution for tan^2(θ)-2tan(θ)=0 ?
The general solution for tan^2(θ)-2tan(θ)=0 is θ=1.10714…+pin,θ=pin