What is the general solution for sin^2(θ)-cos^2(θ)=0 ?

The general solution for sin^2(θ)-cos^2(θ)=0 is θ= pi/4+pin,θ=(3pi)/4+pin

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sin^2(θ)-cos^2(θ)=0

sin^{2} (θ) - cos^{2} (θ) = 0

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

Solution steps

sin^{2} (θ) - cos^{2} (θ) = 0

Rewrite using trig identities

- cos (2 θ) = 0

Divide both sides by

- 1

cos (2 θ) = 0

General solutions for

cos (2 θ) = 0

2 θ = \frac{π}{2} + 2 πn, 2 θ = \frac{3 π}{2} + 2 πn

Solve

2 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{4} + πn

Solve

2 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{4} + πn

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

sec (x) = tan (x) + 1

5 cos (2 x) + 1 = 3 cos (2 x)

2 sin (4 x) + 6 = 5

7 sin (x) tan (x) = - 8 tan (x)

sin^{2} (x) + 2 sin (x) - 3 = 0

What is the general solution for sin^2(θ)-cos^2(θ)=0 ?
The general solution for sin^2(θ)-cos^2(θ)=0 is θ= pi/4+pin,θ=(3pi)/4+pin