What is the general solution for sin(θ)=(-1)/2 ?

The general solution for sin(θ)=(-1)/2 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

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sin(θ)=(-1)/2

sin (θ) = \frac{- 1}{2}

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

sin (θ) = \frac{- 1}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

sin (θ) = - \frac{1}{2}

General solutions for

sin (θ) = - \frac{1}{2}

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

tan (x) = \frac{12}{5}

3 cot (x) - 3 = 0

2 tan^{2} (θ) + 5 tan (θ) = 0

cos (θ) - 3 sin (θ) = 1

sec (x) = \frac{1}{2}

What is the general solution for sin(θ)=(-1)/2 ?
The general solution for sin(θ)=(-1)/2 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin