What is the general solution for 2cos(θ)=-sqrt(3) ?

The general solution for 2cos(θ)=-sqrt(3) is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin

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2cos(θ)=-sqrt(3)

2 cos (θ) = - 3

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

Solution steps

2 cos (θ) = - 3

Divide both sides by

2

cos (θ) = - \frac{3}{2}

General solutions for

cos (θ) = - \frac{3}{2}

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

cos (t) = \frac{3}{2}

(cot (θ) + 1) (sin (θ) + 1) = 0

9 sec^{2} (θ) tan (θ) = 12 tan (θ)

3 tan (θ) = 1

2 cos (3 x) - 1 = 0, 0 \leq x \leq 2 π

What is the general solution for 2cos(θ)=-sqrt(3) ?
The general solution for 2cos(θ)=-sqrt(3) is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin