What is the general solution for sec(5 θ/4)=2,0<θ<2pi ?

The general solution for sec(5 θ/4)=2,0<θ<2pi is θ=(4pi}{15},θ=(4pi)/3 ,θ=\frac{28pi)/(15)

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sec(5 θ/4)=2,0<θ<2pi

sec (5 \frac{θ}{4}) = 2, 0 < θ < 2 π

θ = \frac{4 π}{15}, θ = \frac{4 π}{3}, θ = \frac{28 π}{15}

Solution steps

sec (5 \cdot \frac{θ}{4}) = 2, 0 < θ < 2 π

General solutions for

sec (5 \frac{θ}{4}) = 2

5 \cdot \frac{θ}{4} = \frac{π}{3} + 2 πn, 5 \cdot \frac{θ}{4} = \frac{5 π}{3} + 2 πn

Solve

5 \frac{θ}{4} = \frac{π}{3} + 2 πn : θ = \frac{4 π}{15} + \frac{8 πn}{5}

Solve

5 \frac{θ}{4} = \frac{5 π}{3} + 2 πn : θ = \frac{4 π}{3} + \frac{8 πn}{5}

θ = \frac{4 π}{15} + \frac{8 πn}{5}, θ = \frac{4 π}{3} + \frac{8 πn}{5}

Solutions for the range

0 < θ < 2 π

θ = \frac{4 π}{15}, θ = \frac{4 π}{3}, θ = \frac{28 π}{15}

2 sin (\frac{x}{2}) = 1

sin^{2} (x) - 3 cos^{2} (x) = 0

cos (2 x + \frac{π}{3}) = sin (3 x)

y, x = arcsin (y)

2 sin^{2} (x) + 5 sin (x) = 3

What is the general solution for sec(5 θ/4)=2,0<θ<2pi ?
The general solution for sec(5 θ/4)=2,0<θ<2pi is θ=(4pi}{15},θ=(4pi)/3 ,θ=\frac{28pi)/(15)