What is the general solution for 4sin(θ)-2=0 ?

The general solution for 4sin(θ)-2=0 is θ= pi/6+2pin,θ=(5pi)/6+2pin

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4sin(θ)-2=0

4 sin (θ) - 2 = 0

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Solution steps

4 sin (θ) - 2 = 0

Move

2

to the right side

4 sin (θ) = 2

Divide both sides by

4

sin (θ) = \frac{1}{2}

General solutions for

sin (θ) = \frac{1}{2}

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

sin (θ) = - \frac{5}{13}

2 sin^{2} (x) + 5 sin (x) - 3 = 0

- \frac{1}{2} = sin (x)

2 sin (θ) + 4 = 5

2 cos (x) - 3 tan (x) = 0

What is the general solution for 4sin(θ)-2=0 ?
The general solution for 4sin(θ)-2=0 is θ= pi/6+2pin,θ=(5pi)/6+2pin