What is the general solution for 2sin(θ)+4=5 ?

The general solution for 2sin(θ)+4=5 is θ= pi/6+2pin,θ=(5pi)/6+2pin

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2sin(θ)+4=5

2 sin (θ) + 4 = 5

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Solution steps

2 sin (θ) + 4 = 5

Move

4

to the right side

2 sin (θ) = 1

Divide both sides by

2

sin (θ) = \frac{1}{2}

General solutions for

sin (θ) = \frac{1}{2}

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

2 cos (x) - 3 tan (x) = 0

2 sin (θ) + 5 = 4

1 - sin (x) = cos (x)

sec^{2} (x) = sec (x) + 2

(cot (θ) - 3) (2 sin (θ) + 1) = 0

What is the general solution for 2sin(θ)+4=5 ?
The general solution for 2sin(θ)+4=5 is θ= pi/6+2pin,θ=(5pi)/6+2pin