What is the general solution for cos(2x)-sqrt(2)sin(x)=1 ?

The general solution for cos(2x)-sqrt(2)sin(x)=1 is x=(5pi)/4+2pin,x=(7pi)/4+2pin,x=2pin,x=pi+2pin

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cos(2x)-sqrt(2)sin(x)=1

cos (2 x) - 2 sin (x) = 1

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn, x = 2 πn, x = π + 2 πn

Solution steps

cos (2 x) - 2 sin (x) = 1

Subtract

1

from both sides

cos (2 x) - 2 sin (x) - 1 = 0

Rewrite using trig identities

- 2 sin^{2} (x) - sin (x) 2 = 0

Solve by substitution

sin (x) = - \frac{2}{2}, sin (x) = 0

sin (x) = - \frac{2}{2} : x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn, x = 2 πn, x = π + 2 πn

1 + sin (θ) = 3 sin (θ)

sin^{2} (x) - \frac{3}{4} = 0

tan (x) = - 8

- 3 sin (2 x) = 0

sin (x) = 0.35

What is the general solution for cos(2x)-sqrt(2)sin(x)=1 ?
The general solution for cos(2x)-sqrt(2)sin(x)=1 is x=(5pi)/4+2pin,x=(7pi)/4+2pin,x=2pin,x=pi+2pin