What is the general solution for cos(θ)=-1/3 ?

The general solution for cos(θ)=-1/3 is θ=1.91063…+2pin,θ=-1.91063…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(θ)=-1/3

cos (θ) = - \frac{1}{3}

θ = 1.91063 \dots + 2 πn, θ = - 1.91063 \dots + 2 πn

Degrees

θ = 109.47122 \dots^{\circ} + 36 0^{\circ} n, θ = - 109.47122 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = - \frac{1}{3}

Apply trig inverse properties

cos (θ) = - \frac{1}{3}

General solutions for

cos (θ) = - \frac{1}{3}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

θ = arccos (- \frac{1}{3}) + 2 πn, θ = - arccos (- \frac{1}{3}) + 2 πn

θ = arccos (- \frac{1}{3}) + 2 πn, θ = - arccos (- \frac{1}{3}) + 2 πn

Show solutions in decimal form

θ = 1.91063 \dots + 2 πn, θ = - 1.91063 \dots + 2 πn

2 cos (θ) = 2

4 sin (θ) - 1 = 2 sin (θ)

sin (3 θ + \frac{π}{18}) = 1

cos (θ) = \frac{- 1}{2}

2 sin (x) sec (x) = 2 sin (x)

What is the general solution for cos(θ)=-1/3 ?
The general solution for cos(θ)=-1/3 is θ=1.91063…+2pin,θ=-1.91063…+2pin