What is the general solution for 2sin(θ)+6=5 ?

The general solution for 2sin(θ)+6=5 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin(θ)+6=5

2 sin (θ) + 6 = 5

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

2 sin (θ) + 6 = 5

Move

6

to the right side

2 sin (θ) = - 1

Divide both sides by

2

sin (θ) = - \frac{1}{2}

General solutions for

sin (θ) = - \frac{1}{2}

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

3 sin (θ) - 3 = sin (θ)

cos (x) = \frac{15}{17}

6 cos (θ) - 3 = 0

3 cos (θ) + 3 = 2 sin^{2} (θ)

- 33 + 7 csc (\frac{θ}{5} + 2 3^{\circ}) = 53

What is the general solution for 2sin(θ)+6=5 ?
The general solution for 2sin(θ)+6=5 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin