What is the general solution for 2cos(3x-1)=0 ?

The general solution for 2cos(3x-1)=0 is x= 1/3+pi/6+(2pin)/3 ,x= 1/3+pi/2+(2pin)/3

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2cos(3x-1)=0

2 cos (3 x - 1) = 0

x = \frac{1}{3} + \frac{π}{6} + \frac{2 πn}{3}, x = \frac{1}{3} + \frac{π}{2} + \frac{2 πn}{3}

Solution steps

2 cos (3 x - 1) = 0

Divide both sides by

2

cos (3 x - 1) = 0

General solutions for

cos (3 x - 1) = 0

3 x - 1 = \frac{π}{2} + 2 πn, 3 x - 1 = \frac{3 π}{2} + 2 πn

Solve

3 x - 1 = \frac{π}{2} + 2 πn : x = \frac{1}{3} + \frac{π}{6} + \frac{2 πn}{3}

Solve

3 x - 1 = \frac{3 π}{2} + 2 πn : x = \frac{1}{3} + \frac{π}{2} + \frac{2 πn}{3}

x = \frac{1}{3} + \frac{π}{6} + \frac{2 πn}{3}, x = \frac{1}{3} + \frac{π}{2} + \frac{2 πn}{3}

tan (2 x) = \frac{3}{3}

- 8 cos^{2} (θ) + 6 = 2

3 cos (x) - sin (x) = 1

7 sec (θ) + 9 = - 5

1 - 3 cos (x) = sin^{2} (x)

What is the general solution for 2cos(3x-1)=0 ?
The general solution for 2cos(3x-1)=0 is x= 1/3+pi/6+(2pin)/3 ,x= 1/3+pi/2+(2pin)/3