What is the general solution for 16cos(8x)-2=6 ?

The general solution for 16cos(8x)-2=6 is x= pi/(24)+(pin)/4 ,x=(5pi}{24}+\frac{pin)/4

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16cos(8x)-2=6

16 cos (8 x) - 2 = 6

x = \frac{π}{24} + \frac{πn}{4}, x = \frac{5 π}{24} + \frac{πn}{4}

Solution steps

16 cos (8 x) - 2 = 6

Move

2

to the right side

16 cos (8 x) = 8

Divide both sides by

16

cos (8 x) = \frac{1}{2}

General solutions for

cos (8 x) = \frac{1}{2}

8 x = \frac{π}{3} + 2 πn, 8 x = \frac{5 π}{3} + 2 πn

Solve

8 x = \frac{π}{3} + 2 πn : x = \frac{π}{24} + \frac{πn}{4}

Solve

8 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{24} + \frac{πn}{4}

x = \frac{π}{24} + \frac{πn}{4}, x = \frac{5 π}{24} + \frac{πn}{4}

sin (\frac{x}{2}) = cos (x)

4 sin^{2} (θ) - 4 sin (θ) + 1 = 0

2 cos (θ) - 3 = 5 cos (θ) - 5

tan (θ) = \frac{4}{5}

tan^{2} (x) - sec (x) - 1 = 0

What is the general solution for 16cos(8x)-2=6 ?
The general solution for 16cos(8x)-2=6 is x= pi/(24)+(pin)/4 ,x=(5pi}{24}+\frac{pin)/4