What is the general solution for 4cos(10x)+2=2 ?

The general solution for 4cos(10x)+2=2 is x= pi/(20)+(pin)/5 ,x=(3pi}{20}+\frac{pin)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4cos(10x)+2=2

4 cos (10 x) + 2 = 2

x = \frac{π}{20} + \frac{πn}{5}, x = \frac{3 π}{20} + \frac{πn}{5}

Solution steps

4 cos (10 x) + 2 = 2

Subtract

2

from both sides

4 cos (10 x) + 2 - 2 = 2 - 2

Simplify

4 cos (10 x) = 0

Divide both sides by

4

cos (10 x) = 0

General solutions for

cos (10 x) = 0

10 x = \frac{π}{2} + 2 πn, 10 x = \frac{3 π}{2} + 2 πn

Solve

10 x = \frac{π}{2} + 2 πn : x = \frac{π}{20} + \frac{πn}{5}

Solve

10 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{20} + \frac{πn}{5}

x = \frac{π}{20} + \frac{πn}{5}, x = \frac{3 π}{20} + \frac{πn}{5}

sin (x) = - \frac{3}{4}

sin (2 x - \frac{π}{3}) = \frac{1}{2}

23 sin (2Θ) = 3, 0 \leq Θ \leq 2 π

4 cos^{2} (x) = 5 + 4 sin (x)

2 sin^{2} (x) + 3 sin (x) = 0

What is the general solution for 4cos(10x)+2=2 ?
The general solution for 4cos(10x)+2=2 is x= pi/(20)+(pin)/5 ,x=(3pi}{20}+\frac{pin)/5