What is the general solution for 2sin(4x)-sqrt(2)=0 ?

The general solution for 2sin(4x)-sqrt(2)=0 is x= pi/(16)+(pin)/2 ,x=(3pi}{16}+\frac{pin)/2

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2sin(4x)-sqrt(2)=0

2 sin (4 x) - 2 = 0

x = \frac{π}{16} + \frac{πn}{2}, x = \frac{3 π}{16} + \frac{πn}{2}

Solution steps

2 sin (4 x) - 2 = 0

Move

2

to the right side

2 sin (4 x) = 2

Divide both sides by

2

sin (4 x) = \frac{2}{2}

General solutions for

sin (4 x) = \frac{2}{2}

4 x = \frac{π}{4} + 2 πn, 4 x = \frac{3 π}{4} + 2 πn

Solve

4 x = \frac{π}{4} + 2 πn : x = \frac{π}{16} + \frac{πn}{2}

Solve

4 x = \frac{3 π}{4} + 2 πn : x = \frac{3 π}{16} + \frac{πn}{2}

x = \frac{π}{16} + \frac{πn}{2}, x = \frac{3 π}{16} + \frac{πn}{2}

6 tan (x) sin (x) = 7 sin (x)

cos (2 x) + cos (x) + 1 = 0

3 tan^{4} (x) - 10 tan^{2} (x) + 3 = 0

9 sec (x) csc (x) = 18 csc (x)

2 sin^{2} (x) = 2 - cos (x)

What is the general solution for 2sin(4x)-sqrt(2)=0 ?
The general solution for 2sin(4x)-sqrt(2)=0 is x= pi/(16)+(pin)/2 ,x=(3pi}{16}+\frac{pin)/2