What is the general solution for -4cos(5x)+1=1 ?

The general solution for -4cos(5x)+1=1 is x= pi/(10)+(2pin)/5 ,x=(3pi}{10}+\frac{2pin)/5

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-4cos(5x)+1=1

- 4 cos (5 x) + 1 = 1

x = \frac{π}{10} + \frac{2 πn}{5}, x = \frac{3 π}{10} + \frac{2 πn}{5}

Solution steps

- 4 cos (5 x) + 1 = 1

Subtract

1

from both sides

- 4 cos (5 x) + 1 - 1 = 1 - 1

Simplify

- 4 cos (5 x) = 0

Divide both sides by

- 4

cos (5 x) = 0

General solutions for

cos (5 x) = 0

5 x = \frac{π}{2} + 2 πn, 5 x = \frac{3 π}{2} + 2 πn

Solve

5 x = \frac{π}{2} + 2 πn : x = \frac{π}{10} + \frac{2 πn}{5}

Solve

5 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{10} + \frac{2 πn}{5}

x = \frac{π}{10} + \frac{2 πn}{5}, x = \frac{3 π}{10} + \frac{2 πn}{5}

- 5 sin (x) = - 2 cos^{2} (x) + 4

6 sin^{2} (θ) - 13 sin (θ) + 7 = 0

sin (x) = 0.1

3 sin^{2} (x) + 6 sin (x) + 3 = 0

3 sin (x) - 4 = sin (x) - 2

What is the general solution for -4cos(5x)+1=1 ?
The general solution for -4cos(5x)+1=1 is x= pi/(10)+(2pin)/5 ,x=(3pi}{10}+\frac{2pin)/5