What is the general solution for cos(θ)sin(θ)-2cos(θ)=0 ?

The general solution for cos(θ)sin(θ)-2cos(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin

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cos(θ)sin(θ)-2cos(θ)=0

cos (θ) sin (θ) - 2 cos (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

cos (θ) sin (θ) - 2 cos (θ) = 0

Factor

cos (θ) sin (θ) - 2 cos (θ) : cos (θ) (sin (θ) - 2)

cos (θ) (sin (θ) - 2) = 0

Solving each part separately

cos (θ) = 0 or sin (θ) - 2 = 0

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

sin (θ) - 2 = 0 :

No Solution

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

y, x = tan^{2} (y)

tan (θ) = \frac{7}{3}

sin (4 θ) - sin (2 θ) = 0

tan (x) sin (x) - tan (x) = 0

cos^{2} (θ) - 7 cos (θ) + 12 = 0

What is the general solution for cos(θ)sin(θ)-2cos(θ)=0 ?
The general solution for cos(θ)sin(θ)-2cos(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin