What is the general solution for 3tan^2(θ)=1 ?

The general solution for 3tan^2(θ)=1 is θ=0.52359…+pin,θ=-0.52359…+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3tan^2(θ)=1

3 tan^{2} (θ) = 1

θ = 0.52359 \dots + πn, θ = - 0.52359 \dots + πn

Solution steps

3 tan^{2} (θ) = 1

Solve by substitution

tan (θ) = \frac{1}{3}, tan (θ) = - \frac{1}{3}

tan (θ) = \frac{1}{3} : θ = arctan (\frac{1}{3}) + πn

tan (θ) = - \frac{1}{3} : θ = arctan (- \frac{1}{3}) + πn

Combine all the solutions

θ = arctan (\frac{1}{3}) + πn, θ = arctan (- \frac{1}{3}) + πn

Show solutions in decimal form

θ = 0.52359 \dots + πn, θ = - 0.52359 \dots + πn

3 cos (x) = 2 sin^{2} (x)

2 sec^{2} (x) - tan^{4} (x) = - 1

4 sin (θ) = 2

6 cos^{2} (x) = 3

3 sin (x) + 3 = sin (x)

What is the general solution for 3tan^2(θ)=1 ?
The general solution for 3tan^2(θ)=1 is θ=0.52359…+pin,θ=-0.52359…+pin