What is the general solution for 2cos(2x)-sqrt(2)=0 ?

The general solution for 2cos(2x)-sqrt(2)=0 is x= pi/8+pin,x=(7pi)/8+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos(2x)-sqrt(2)=0

2 cos (2 x) - 2 = 0

x = \frac{π}{8} + πn, x = \frac{7 π}{8} + πn

Solution steps

2 cos (2 x) - 2 = 0

Move

2

to the right side

2 cos (2 x) = 2

Divide both sides by

2

cos (2 x) = \frac{2}{2}

General solutions for

cos (2 x) = \frac{2}{2}

2 x = \frac{π}{4} + 2 πn, 2 x = \frac{7 π}{4} + 2 πn

Solve

2 x = \frac{π}{4} + 2 πn : x = \frac{π}{8} + πn

Solve

2 x = \frac{7 π}{4} + 2 πn : x = \frac{7 π}{8} + πn

x = \frac{π}{8} + πn, x = \frac{7 π}{8} + πn

3 tan^{2} (x) + 4 sec (x) = - 4

tan (x + 2 0^{\circ}) \cdot tan (x - 2 0^{\circ}) = 1

18 cos (10 x) + 2 = 10

cos (2 θ) = sin (2 θ)

2 cos (\frac{x}{2}) = 3

What is the general solution for 2cos(2x)-sqrt(2)=0 ?
The general solution for 2cos(2x)-sqrt(2)=0 is x= pi/8+pin,x=(7pi)/8+pin