What is the general solution for tan(a)=1 ?

The general solution for tan(a)=1 is a= pi/4+pin

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tan(a)=1

tan (a) = 1

a = \frac{π}{4} + πn

Degrees

a = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

tan (a) = 1

General solutions for

tan (a) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

a = \frac{π}{4} + πn

a = \frac{π}{4} + πn

cos (2 θ) = 2, cos^{2} (θ) - 1 = 2, (- \frac{3}{5})^{2} - 1 = - \frac{7}{25}

2 sin (2 θ) = 1, 0 \leq θ \leq 2 π

2 cos^{2} (x) - 3 sin (x) = 3

14 cos (θ) - 5 = 5 cos (θ) - 5

- 4 sin (2 θ) = 5 cos (2 θ)

What is the general solution for tan(a)=1 ?
The general solution for tan(a)=1 is a= pi/4+pin