What is the general solution for 14cos(θ)-5=5cos(θ)-5 ?

The general solution for 14cos(θ)-5=5cos(θ)-5 is θ= pi/2+2pin,θ=(3pi)/2+2pin

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14cos(θ)-5=5cos(θ)-5

14 cos (θ) - 5 = 5 cos (θ) - 5

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

14 cos (θ) - 5 = 5 cos (θ) - 5

Solve by substitution

cos (θ) = 0

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

- 4 sin (2 θ) = 5 cos (2 θ)

tan (A) = \frac{3}{4}

2 sin (3 x) + 1 = 0

3 sin (θ) = cos (θ), 0 \leq θ \leq 2 π

cos (2 θ) = - \frac{2}{2}

What is the general solution for 14cos(θ)-5=5cos(θ)-5 ?
The general solution for 14cos(θ)-5=5cos(θ)-5 is θ= pi/2+2pin,θ=(3pi)/2+2pin