What is the general solution for sqrt(3)sin(θ)=cos(θ),0<= θ<= 2pi ?

The general solution for sqrt(3)sin(θ)=cos(θ),0<= θ<= 2pi is θ= pi/6 ,θ=(7pi)/6

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sqrt(3)sin(θ)=cos(θ),0<= θ<= 2pi

3 sin (θ) = cos (θ), 0 \leq θ \leq 2 π

θ = \frac{π}{6}, θ = \frac{7 π}{6}

Solution steps

3 sin (θ) = cos (θ), 0 \leq θ \leq 2 π

Rewrite using trig identities

3 tan (θ) = 1

Divide both sides by

3

tan (θ) = \frac{3}{3}

General solutions for

tan (θ) = \frac{3}{3}

θ = \frac{π}{6} + πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{π}{6}, θ = \frac{7 π}{6}

cos (2 θ) = - \frac{2}{2}

tan (\frac{θ}{2} + \frac{π}{3}) = - 1

sin (2 x) = 3 cos (2 x)

sec (x) = - 2, 0 \leq x \leq 2 π

t, g = sin (2 π f t)

What is the general solution for sqrt(3)sin(θ)=cos(θ),0<= θ<= 2pi ?
The general solution for sqrt(3)sin(θ)=cos(θ),0<= θ<= 2pi is θ= pi/6 ,θ=(7pi)/6