What is the general solution for sqrt(3)tan(θ)+1=0,0<= θ<= 2pi ?

The general solution for sqrt(3)tan(θ)+1=0,0<= θ<= 2pi is θ=(5pi)/6 ,θ=(11pi)/6

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sqrt(3)tan(θ)+1=0,0<= θ<= 2pi

3 tan (θ) + 1 = 0, 0 \leq θ \leq 2 π

θ = \frac{5 π}{6}, θ = \frac{11 π}{6}

Solution steps

3 tan (θ) + 1 = 0, 0 \leq θ \leq 2 π

Move

1

to the right side

3 tan (θ) = - 1

Divide both sides by

3

tan (θ) = - \frac{3}{3}

General solutions for

tan (θ) = - \frac{3}{3}

θ = \frac{5 π}{6} + πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{5 π}{6}, θ = \frac{11 π}{6}

tan (x) = tan^{2} (x)

y, sin (x y) = x

tan (x) sec (x) = tan (x)

1 - sin (2 x) = cos (2 x)

sin (2 x - 5 \frac{π}{6}) = - \frac{1}{2}, 0 \leq x \leq 2 π

What is the general solution for sqrt(3)tan(θ)+1=0,0<= θ<= 2pi ?
The general solution for sqrt(3)tan(θ)+1=0,0<= θ<= 2pi is θ=(5pi)/6 ,θ=(11pi)/6