What is the general solution for sin(2x-5 pi/6)=-1/2 ,0<= x<= 2pi ?

Q: What is the general solution for sin(2x-5 pi/6)=-1/2 ,0<= x<= 2pi ?

The general solution for sin(2x-5 pi/6)=-1/2 ,0<= x<= 2pi is x=pi,x=(4pi)/3 ,x=2pi,x=0,x= pi/3

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sin(2x-5 pi/6)=-1/2 ,0<= x<= 2pi

Solution

sin (2 x - 5 \frac{π}{6}) = - \frac{1}{2}, 0 \leq x \leq 2 π

Solution

x = π, x = \frac{4 π}{3}, x = 2 π, x = 0, x = \frac{π}{3}

Degrees

x = 18 0^{\circ}, x = 24 0^{\circ}, x = 36 0^{\circ}, x = 0^{\circ}, x = 6 0^{\circ}

Solution steps

sin (2 x - 5 \cdot \frac{π}{6}) = - \frac{1}{2}, 0 \leq x \leq 2 π

General solutions for

sin (2 x - 5 \frac{π}{6}) = - \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

2 x - 5 \cdot \frac{π}{6} = \frac{7 π}{6} + 2 πn, 2 x - 5 \cdot \frac{π}{6} = \frac{11 π}{6} + 2 πn

2 x - 5 \cdot \frac{π}{6} = \frac{7 π}{6} + 2 πn, 2 x - 5 \cdot \frac{π}{6} = \frac{11 π}{6} + 2 πn

Solve

2 x - 5 \frac{π}{6} = \frac{7 π}{6} + 2 πn : x = πn + π

2 x - 5 \cdot \frac{π}{6} = \frac{7 π}{6} + 2 πn

Multiply

5 \cdot \frac{π}{6} : \frac{5 π}{6}

5 \cdot \frac{π}{6}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 5}{6}

2 x - \frac{5 π}{6} = \frac{7 π}{6} + 2 πn

Move

\frac{5 π}{6}

to the right side

2 x - \frac{5 π}{6} = \frac{7 π}{6} + 2 πn

Add

\frac{5 π}{6}

to both sides

2 x - \frac{5 π}{6} + \frac{5 π}{6} = \frac{7 π}{6} + 2 πn + \frac{5 π}{6}

Simplify

2 x - \frac{5 π}{6} + \frac{5 π}{6} = \frac{7 π}{6} + 2 πn + \frac{5 π}{6}

Simplify

2 x - \frac{5 π}{6} + \frac{5 π}{6} : 2 x

2 x - \frac{5 π}{6} + \frac{5 π}{6}

Add similar elements:

- \frac{5 π}{6} + \frac{5 π}{6} = 0

= 2 x

Simplify

\frac{7 π}{6} + 2 πn + \frac{5 π}{6} : 2 πn + 2 π

\frac{7 π}{6} + 2 πn + \frac{5 π}{6}

Group like terms

= 2 πn + \frac{7 π}{6} + \frac{5 π}{6}

Combine the fractions

\frac{7 π}{6} + \frac{5 π}{6} : 2 π

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{7 π + 5 π}{6}

Add similar elements:

7 π + 5 π = 12 π

= \frac{12 π}{6}

Divide the numbers:

\frac{12}{6} = 2

= 2 π

= 2 πn + 2 π

2 x = 2 πn + 2 π

2 x = 2 πn + 2 π

2 x = 2 πn + 2 π

Divide both sides by

2

2 x = 2 πn + 2 π

Divide both sides by

2

\frac{2 x}{2} = \frac{2 πn}{2} + \frac{2 π}{2}

Simplify

x = πn + π

x = πn + π

Solve

2 x - 5 \frac{π}{6} = \frac{11 π}{6} + 2 πn : x = πn + \frac{4 π}{3}

2 x - 5 \cdot \frac{π}{6} = \frac{11 π}{6} + 2 πn

Multiply

5 \cdot \frac{π}{6} : \frac{5 π}{6}

5 \cdot \frac{π}{6}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 5}{6}

2 x - \frac{5 π}{6} = \frac{11 π}{6} + 2 πn

Move

\frac{5 π}{6}

to the right side

2 x - \frac{5 π}{6} = \frac{11 π}{6} + 2 πn

Add

\frac{5 π}{6}

to both sides

2 x - \frac{5 π}{6} + \frac{5 π}{6} = \frac{11 π}{6} + 2 πn + \frac{5 π}{6}

Simplify

2 x - \frac{5 π}{6} + \frac{5 π}{6} = \frac{11 π}{6} + 2 πn + \frac{5 π}{6}

Simplify

2 x - \frac{5 π}{6} + \frac{5 π}{6} : 2 x

2 x - \frac{5 π}{6} + \frac{5 π}{6}

Add similar elements:

- \frac{5 π}{6} + \frac{5 π}{6} = 0

= 2 x

Simplify

\frac{11 π}{6} + 2 πn + \frac{5 π}{6} : 2 πn + \frac{8 π}{3}

\frac{11 π}{6} + 2 πn + \frac{5 π}{6}

Group like terms

= 2 πn + \frac{5 π}{6} + \frac{11 π}{6}

Combine the fractions

\frac{5 π}{6} + \frac{11 π}{6} : \frac{8 π}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{5 π + 11 π}{6}

Add similar elements:

5 π + 11 π = 16 π

= \frac{16 π}{6}

Cancel the common factor:

2

= \frac{8 π}{3}

= 2 πn + \frac{8 π}{3}

2 x = 2 πn + \frac{8 π}{3}

2 x = 2 πn + \frac{8 π}{3}

2 x = 2 πn + \frac{8 π}{3}

Divide both sides by

2

2 x = 2 πn + \frac{8 π}{3}

Divide both sides by

2

\frac{2 x}{2} = \frac{2 πn}{2} + \frac{\frac{8 π}{3}}{2}

Simplify

\frac{2 x}{2} = \frac{2 πn}{2} + \frac{\frac{8 π}{3}}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{2 πn}{2} + \frac{\frac{8 π}{3}}{2} : πn + \frac{4 π}{3}

\frac{2 πn}{2} + \frac{\frac{8 π}{3}}{2}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

\frac{\frac{8 π}{3}}{2} = \frac{4 π}{3}

\frac{\frac{8 π}{3}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{8 π}{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{8 π}{6}

Cancel the common factor:

2

= \frac{4 π}{3}

= πn + \frac{4 π}{3}

x = πn + \frac{4 π}{3}

x = πn + \frac{4 π}{3}

x = πn + \frac{4 π}{3}

x = πn + π, x = πn + \frac{4 π}{3}

Solutions for the range

0 \leq x \leq 2 π

x = π, x = \frac{4 π}{3}, x = 2 π, x = 0, x = \frac{π}{3}

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Frequently Asked Questions (FAQ)

What is the general solution for sin(2x-5 pi/6)=-1/2 ,0<= x<= 2pi ?
The general solution for sin(2x-5 pi/6)=-1/2 ,0<= x<= 2pi is x=pi,x=(4pi)/3 ,x=2pi,x=0,x= pi/3