What is the general solution for sin(9x)=-(sqrt(3))/2 ?

The general solution for sin(9x)=-(sqrt(3))/2 is x=(4pi}{27}+(2pin)/9 ,x=(5pi)/(27)+\frac{2pin)/9

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sin(9x)=-(sqrt(3))/2

sin (9 x) = - \frac{3}{2}

x = \frac{4 π}{27} + \frac{2 πn}{9}, x = \frac{5 π}{27} + \frac{2 πn}{9}

Solution steps

sin (9 x) = - \frac{3}{2}

General solutions for

sin (9 x) = - \frac{3}{2}

9 x = \frac{4 π}{3} + 2 πn, 9 x = \frac{5 π}{3} + 2 πn

Solve

9 x = \frac{4 π}{3} + 2 πn : x = \frac{4 π}{27} + \frac{2 πn}{9}

Solve

9 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{27} + \frac{2 πn}{9}

x = \frac{4 π}{27} + \frac{2 πn}{9}, x = \frac{5 π}{27} + \frac{2 πn}{9}

cos (θ) = \frac{5}{7}

2 sin (2 x) - 3 sin (x) = 0

cos (t) = - \frac{2}{2}

2 sin^{2} (3 x) = 1

sin^{2} (θ) - 16 = 0

What is the general solution for sin(9x)=-(sqrt(3))/2 ?
The general solution for sin(9x)=-(sqrt(3))/2 is x=(4pi}{27}+(2pin)/9 ,x=(5pi)/(27)+\frac{2pin)/9