What is the general solution for sin(9x)=-(sqrt(3))/2 ?

The general solution for sin(9x)=-(sqrt(3))/2 is x=(4pi}{27}+(2pin)/9 ,x=(5pi)/(27)+\frac{2pin)/9

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Popular >

sin(9x)=-(sqrt(3))/2

Solution

sin (9 x) = - \frac{3}{2}

Solution

x = \frac{4 π}{27} + \frac{2 πn}{9}, x = \frac{5 π}{27} + \frac{2 πn}{9}

Degrees

x = 26.66666 \dots^{\circ} + 4 0^{\circ} n, x = 33.33333 \dots^{\circ} + 4 0^{\circ} n

Solution steps

sin (9 x) = - \frac{3}{2}

General solutions for

sin (9 x) = - \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

9 x = \frac{4 π}{3} + 2 πn, 9 x = \frac{5 π}{3} + 2 πn

9 x = \frac{4 π}{3} + 2 πn, 9 x = \frac{5 π}{3} + 2 πn

Solve

9 x = \frac{4 π}{3} + 2 πn : x = \frac{4 π}{27} + \frac{2 πn}{9}

9 x = \frac{4 π}{3} + 2 πn

Divide both sides by

9

9 x = \frac{4 π}{3} + 2 πn

Divide both sides by

9

\frac{9 x}{9} = \frac{\frac{4 π}{3}}{9} + \frac{2 πn}{9}

Simplify

\frac{9 x}{9} = \frac{\frac{4 π}{3}}{9} + \frac{2 πn}{9}

Simplify

\frac{9 x}{9} : x

\frac{9 x}{9}

Divide the numbers:

\frac{9}{9} = 1

= x

Simplify

\frac{\frac{4 π}{3}}{9} + \frac{2 πn}{9} : \frac{4 π}{27} + \frac{2 πn}{9}

\frac{\frac{4 π}{3}}{9} + \frac{2 πn}{9}

\frac{\frac{4 π}{3}}{9} = \frac{4 π}{27}

\frac{\frac{4 π}{3}}{9}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{4 π}{3 \cdot 9}

Multiply the numbers:

3 \cdot 9 = 27

= \frac{4 π}{27}

= \frac{4 π}{27} + \frac{2 πn}{9}

x = \frac{4 π}{27} + \frac{2 πn}{9}

x = \frac{4 π}{27} + \frac{2 πn}{9}

x = \frac{4 π}{27} + \frac{2 πn}{9}

Solve

9 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{27} + \frac{2 πn}{9}

9 x = \frac{5 π}{3} + 2 πn

Divide both sides by

9

9 x = \frac{5 π}{3} + 2 πn

Divide both sides by

9

\frac{9 x}{9} = \frac{\frac{5 π}{3}}{9} + \frac{2 πn}{9}

Simplify

\frac{9 x}{9} = \frac{\frac{5 π}{3}}{9} + \frac{2 πn}{9}

Simplify

\frac{9 x}{9} : x

\frac{9 x}{9}

Divide the numbers:

\frac{9}{9} = 1

= x

Simplify

\frac{\frac{5 π}{3}}{9} + \frac{2 πn}{9} : \frac{5 π}{27} + \frac{2 πn}{9}

\frac{\frac{5 π}{3}}{9} + \frac{2 πn}{9}

\frac{\frac{5 π}{3}}{9} = \frac{5 π}{27}

\frac{\frac{5 π}{3}}{9}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 π}{3 \cdot 9}

Multiply the numbers:

3 \cdot 9 = 27

= \frac{5 π}{27}

= \frac{5 π}{27} + \frac{2 πn}{9}

x = \frac{5 π}{27} + \frac{2 πn}{9}

x = \frac{5 π}{27} + \frac{2 πn}{9}

x = \frac{5 π}{27} + \frac{2 πn}{9}

x = \frac{4 π}{27} + \frac{2 πn}{9}, x = \frac{5 π}{27} + \frac{2 πn}{9}

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Frequently Asked Questions (FAQ)

What is the general solution for sin(9x)=-(sqrt(3))/2 ?
The general solution for sin(9x)=-(sqrt(3))/2 is x=(4pi}{27}+(2pin)/9 ,x=(5pi)/(27)+\frac{2pin)/9