What is the general solution for cos(θ)=-sin(-θ) ?

The general solution for cos(θ)=-sin(-θ) is θ= pi/4+pin

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cos(θ)=-sin(-θ)

cos (θ) = - sin (- θ)

θ = \frac{π}{4} + πn

Solution steps

cos (θ) = - sin (- θ)

Rewrite using trig identities

cos (θ) = sin (θ)

Subtract

sin (θ)

from both sides

cos (θ) - sin (θ) = 0

Rewrite using trig identities

1 - tan (θ) = 0

Move

1

to the right side

- tan (θ) = - 1

Divide both sides by

- 1

tan (θ) = 1

General solutions for

tan (θ) = 1

θ = \frac{π}{4} + πn

sin (x) - 3 cos (x) = 3

cot^{2} (x) - 2 csc (x) = - 1

3 csc (x) + csc (x) cot (x) = 0

- 3 cos^{2} (θ) - 10 cos (θ) = - 3 cos (θ) - 6

- 4 sin (x) = - cos^{2} (x) + 4

What is the general solution for cos(θ)=-sin(-θ) ?
The general solution for cos(θ)=-sin(-θ) is θ= pi/4+pin