What is the general solution for 4tan^2(x)-12=0 ?

The general solution for 4tan^2(x)-12=0 is x= pi/3+pin,x=(2pi)/3+pin

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4tan^2(x)-12=0

4 tan^{2} (x) - 12 = 0

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

Solution steps

4 tan^{2} (x) - 12 = 0

Solve by substitution

tan (x) = 3, tan (x) = - 3

tan (x) = 3 : x = \frac{π}{3} + πn

tan (x) = - 3 : x = \frac{2 π}{3} + πn

Combine all the solutions

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

tan (θ) - \frac{1}{3} = 0

tan (\frac{x}{2} + \frac{π}{3}) = 1

- cot (x) + csc (x) = 1

cot (\frac{x}{2}) = 0

sin^{2} (θ) = 2 sin (θ) + 3

What is the general solution for 4tan^2(x)-12=0 ?
The general solution for 4tan^2(x)-12=0 is x= pi/3+pin,x=(2pi)/3+pin